问题 填空题

设等比数列an中,每项均是正数,且a5a6=81,则 log3a1+log3a2+…+log3a10=______.

答案

∵等比数列{an}中,每项均是正数,且a5a6=81,

∴log3a1+log3a2+…+log3a10=log3(a1?a2?a3…a10

=log3(a5a65

=log3320

=20.

故答案:20.

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