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问题 填空题
函数f(x)=22x-
5
2
×2x+1的最小值是______．
答案

由题意f(x)=22x-

5
2
×2x+1=(2x-
5
4
)2-
9
16

当2x=

5
4
即x=log2
5
4
时，函数的最小值为-
9
16

故答案为-

9
16

单项选择题

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A．allocating storage

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D．assigning storage
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B.硫甲丙脯酸

C.哌唑嗪

D.硝普钠

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