问题
填空题
设{an}是等比数列,公比q=
|
答案
Tn =
-17a1 [1-(
)n ]2 1- 2 a1 [1-(
)2n ]2 1- 2 a1(
)n2
=
•1 1- 2 (
)2n -17(2
)n +162 (
)n2
=
•[(1 1- 2
)n+2
-17]16 (
)n2
因为(
)n+2
≧8,当且仅当(16 (
)n2
)n=4,2
即n=4时取等号,所以当n0=4时Tn有最大值.