问题 选择题

下列解释实验事实的平衡不正确的是

 实  验解释
A100℃ 0.1 mol/LNa2SO4溶液pH= 6.2H2OH+ + OH
B0.1 mol/L CH3COOH的pH=3CH3COOHCH3COO + H+
C配制FeCl3溶液时加少量盐酸Fe3+ + 3OHFe(OH)3
D用稀硫酸洗涤BaSO4,沉淀损失小BaSO4(s) Ba2+(aq) + SO42(aq)
 

答案

答案:C

题目分析:A、温度升高,H2O的电离平衡向右移动,正确;B、CH3COOH为弱酸,部分电离,存在电离平衡:CH3COOH CH3COO‾+H+,正确;C、配制FeCl3溶液时加少量盐酸,目的是抑制Fe3+的水解,Fe3++3H2OFe(OH)3+3H+,错误;D、用稀硫酸洗涤BaSO4,使BaSO4的沉淀溶解平衡:BaSO4(s) Ba2+(aq) + SO42(aq),向左移动,正确。

问答题

列举春秋五霸,简要分析他们能够称霸的共同原因。

                                                                                                                                                            

                                                                                                                                                            

                                                                                                                                                            

                                                                                                                                                            

                                                                                                                                                            

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