问题
选择题
设f1(x)=
|
答案
由题意可得f1(0)=
=2,2 1+0
a1=
=f1(0)-1 f1(0)+2
=2-1 2+2
,1 4
由因为fn+1(x)=f1[fn(x)],
所以an+1=
=fn+1(0)-1 fn+1(0)+2
=f1[fn(0)]-1 f1[fn(0)]+2
=
-12 1+fn(0)
+22 1+fn(0)
=-1-fn(0) 4+2fn(0)
•1 2
=-fn(0)-1 fn(0)+2
an,1 2
故数列{an}为公比为-
的等比数列,1 2
故a2013=a1×(-
)2012=1 2
×(-1 4
)2012=(1 2
)20141 2
故选C