设函数f（x）=x2-4x+3，g（x）=3x-2，则f（g（x））＞0的解集是______．
∵f（x）=x2-4x+3，g（x）=3x-2，
∴f（g（x））=（3x-2）2-4（3x-2）+3
=（3x）2-8•3x+15=（3x-3）（3x-5），
由（3x-3）（3x-5）＞0解得3x＞5或3x＜3，
解得x＜1或x＞log35，
故所求解集为：（-∞，1）∪（log35，+∞），
故答案为：（-∞，1）∪（log35，+∞）
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