问题
解答题
(1)-32÷[-
(2)(1
(3)-36×(
|
答案
(1)原式=-9÷(-
)9 4
=9×4 9
=4;
(2)原式=
×(-24)+4 3
×(-24)-2.75×(-24)-1-231 8
=-32-3+66-1-8
=22;
(3)原式=[(-36)×
-(-36)×1 4
-(-36)×1 9
]÷(-2)1 12
=[-9+4+3]÷(-2)
=(-2)÷(-2)
=1.