已知：关于x的一元二次方程x2+（2m-4）x+m2=0有两个相等的实数根，求m的值，并求出方程的解．
∵关于x的一元二次方程x2+（2m-4）x+m2=0有两个相等的实数根，
∴△=0，即△=（2m-4）2-4m2=-16m+16=0，
解方程-16m+16=0，得m=1．
所以原方程变为：x2-2x+1=0，（x-1）2=0，则x1=x2=1．
因此所求的m的值为1，此时方程的解为x1=x2=1．
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| 1. __________ lost his school ID card. | ||||
| A. John B. Robert C. Mary D. Steve | ||||
| 2. If you lost your watch, you will call John at __________. | ||||
| A. 597 -4393 B. 235 -0285 C. 685 - 6034 D. 597 -0285 | ||||
| 3. You can find a __________ in the lost and found case. | ||||
| A. watch B. computer game C. gold ring D. school ID card | ||||
| 4. 235-0285 is __________ telephone number. | ||||
| A. John's B. Francisco's C. Mary's D. Steve's | ||||
| 5. If Alan lost his computer game, he should call __________. | ||||
| A. John B. Robert C. Mary D. Steve |