问题
问答题 计算题
某一输水管线长1100m，管线流量为720m3/h，求该管线的沿程水头损失？（阻力系数A=6.84x10-2，修正系数K=1.03）
答案
参考答案：
Q=720m3/h=0.2m3/s
hf=KAlQ2=1.03X6.84X10-2X1100x0.22=3.1（m）
该管线的沿程水头损失为3.1m
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某一输水管线长1100m，管线流量为720m3/h，求该管线的沿程水头损失？（阻力系数A=6.84x10-2，修正系数K=1.03）
参考答案：
Q=720m3/h=0.2m3/s
hf=KAlQ2=1.03X6.84X10-2X1100x0.22=3.1（m）
该管线的沿程水头损失为3.1m
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