问题
解答题
计算: (1)7
(2)(-0.5)÷1
(3)-7×
(4)(
(5)-32-
|
答案
(1)7
-53 4
-34 11
-61 4
+97 11
+21 4 1 4
=(7
-33 4
+91 4
+21 4
)-(51 4
+64 11
)7 11
=16-12
=4;
(2)(-0.5)÷1
×(-11)5 6
=
×1 2
×(-11)6 11
=-3;
(3)-7×
+(-5)×(-5 4
)-5 4 2 5
=(-7+5)×
-5 4 2 5
=(-2)×
-5 4 2 5
=-
-5 2 2 5
=-2
;9 10
(4)(
-2 3
-11 12
)×(-60)14 15
=-
×60+2 3
×60+11 12
×6014 15
=-40+55+56
=71;
(5)-32-
×[(-5)2×(-1 3
)-240÷(-4)×3 5
]1 4
=-9-
×[25×(-1 3
)+60×3 5
]1 4
=-9-
×[-15+15]1 3
=-9-
×01 3
=-9-0
=-9.