徐某在给个体工商户蒋某开出的汇票上除记载了必要事项外，还记载_爱下问搜题

搜题请搜索小程序“爱下问搜题”

问题单项选择题

徐某在给个体工商户蒋某开出的汇票上除记载了必要事项外，还记载有“该汇票在蒋某支付货物给我后才生效力”的字样，此时该汇票的效力如何：

A．该汇票在蒋某支付货物后方产生效力

B．该汇票生效，但该记载事项不具有汇票上的效力

C．该汇票不产生效力

D．该汇票的效力由当事人协商决定

答案

参考答案：B

解析：理由：本题考查汇票的效力。《票据法》第24条规定：“汇票上可以记载本法规定事项以外的其他出票事项，但是该记载事项不具有汇票上的效力。”显然，只要汇票的必要记载事项合法、完整，则该汇票就产生了法律效力，而不论其他记载事项的内容，故选项B正确。注意，要与汇票的承兑相区别。《票据法》第43条规定：“付款人承兑汇票，不得附有条件；承兑附有条件的，视为拒绝承兑。”这与该法第24条规定不同。

问答题

【说明】希赛教育集团公司为发展生产向社会公开招聘M个工种的工作人员，每个工种各有不同的编号(1至M)和计划招聘人数。每位应聘者需申报两个工种，并参加公司组织的考试。公司将按应聘者的成绩从高分至低分的顺序进行排队录取。公司的录取原则是：从高分到低分依次对每位应聘者先按其第一志愿录取；当不能按其第一志愿录取时，便将他的成绩扣去5分后，重新排队，并按其第二志愿考虑录取。程序为输出各工种实际招聘的应聘人员，每个工种都保留一个录取者的有序队列。录取处理循环直至招聘额满或已对全部应聘者都做了录取处理。程序中，类型STU包含有应聘者的基本信息：编号、成绩、志愿、排队成绩和录取志愿号。数组rz[]的每个元素对应一个工种，包含有计划招聘人数和已录取的人数。【程序】 #include＜stdio.h＞ #include＜malloc.h＞ #define M 20 #define PEMARK 5 typedef struct stu{ int no, total, z[2], sortm, zi; struct stu *next; }STU; struct rzmode{ int Imt, count; STU *next; }rz[M]; STU *head=NULL, *over=NULL; int all FILE *fp; char dataf[]="pp07.dat"; print(STU *p){ for(;p!=NULL;p=p-＞next) printf("%d(%d)\t",p-＞no,p-＞total); } insert(STU **p, STU *u){ STU *v, *q; for(q=*p;q!=NULL;v=q, (1) ) if(q-＞sortm＜u-＞sortm)break; if(q==*p) (2) ; else (3) ; U-＞next=q; } main(){ int zn, i, no, total, z1, z2; STU *p, *v, *q; fp=fopen(dataf, "r"); if(fp==NULL){ printf("Can’t open file %s.\n",dataf); exit(0); } fscanf(fp, "%d",&zn); for(all=0，i=1；i＜=zn;i++){ fscanf(fp,"%d",&rz[i].Imt); rz[i].count=0;rz[i].next=NULL; all+= (4) ; } for(;;){ if((fscanf(fp, "%d%d%d%d",&no,&total,&z1,&z2))!=4) break; p=(STU*)malloc(sizeof(STU)); p-＞no=no; p-＞total=p-＞sortm=total; p-＞zi=0;p-＞z[0]=z1;p-＞z[1]=z2; (5) ; } fclose(fp); for(;all && head !=NULL;){ p=head; head=head-＞next; if(rz[p-＞z[p-＞zi]].count＜ (6) ){ rz[p-＞z[p-＞zi]].count++; insert(&rz[p-＞z[p-＞zi]].next,p); all--; continue; } if(p-＞zi＞=1){ p-＞next=over;over=p; continue; } p-＞sortm-=DEMARK; (7) ; insed(&head,p); } for(i=1;i＜=zn;i++){ printf("%d:\n",i); print(rz[i].next); printf("\n"); } printf("over:\n");print(head); print(over);printf("\n"); }

阅读理解

A special laboratory at the University of Chicago is busy only at night. It is a dream laboratory where researchers are at work studying dreamers. Their findings have discovered that everyone dreams from three to seven times a night, although in ordinary life a person may remember none or only one of his dreams.

　　While the subjects—usually students—sleep, special machines record their brain waves and eye movements as well as the body movements that signal the end of a dream. Surprisingly, all subjects sleep soundly.

Observers report that a person usually fidgets(烦躁不安) before a dream. Once the dream has started, his body relaxes and his eyes become more active, as if the curtain had gone up on a show. As soon as the machine shows that the dream is over, a buzzer wakens the sleeper. He sits up, records his dream, and goes back to sleep—perhaps to dream some more.

Researchers have found that if the dreamer is wakened immediately after his dream, he can usually recall the entire dream. If he is allowed to sleep even five more minutes, his memory of the dream will have disappeared.

小题1:According to the passage, researchers at the University of Chicago are studying ____.

A．contents of dreams　

B．dreamers while they dream

C．the meaning of dreams

D．the progress of sleeping小题2:Their finding has discovered that _____.

A．everyone dreams every night

B．dreams are easily remembered

C．dreams are likely to be frightening

D．One person dreams only one dream a night小题3:The machines being used in the experiment record _____.

A．the depth of sleep

B．the subjects’ brain waves and eye movements

C．how many dreams a person has

D．what a sleeper dreams during his sleep小题4:A person would be most likely to remember the dream that _____.

A．was of most interest to him

B．occurred immediately after he went to sleep

C．occurred just before he woke up

D．was the longest one to him