问题 单项选择题

When caring for a client who has recently delivered, the nurse assesses the client for urinary retention with overflow. Which of the following provides the most accurate picture of retention with overflow

A.Frequent trips to the bathroom with an average output of 200 to 300 mL per void.

B.Intense urge to urinate with an average output of 250 mL.

C.A varying urge to urinate with an average output of 100 mL.

D.Uterus displaced to the right with increased vaginal bleeding.

答案

参考答案:C

解析:Retention with overflow is a commonly missed nursing assessment. Because the client may be voiding and may not have an urge to void doesn't mean that bladder function has been properly restored. A varying urge to urinate with an average urine output of 100 mL is a classic picture of a client whose bladder is distended and needs to be catheterized to restore normal function.

实验题

在实验室中,可利用碳酸氢钠、氯化钠、氯化铵等物质溶解度的差异,通过饱和食盐水、氨和二氧化碳反应,获得碳酸氢钠晶体,反应原理可用如下化学方程式表示:NH3+CO2+NaCl+H2O    NH4Cl+NaHCO3(晶体)依据此原理,欲制得碳酸钠晶体,某校学生设计了如下实验装置,其中B装置中的试管内是溶有氨和氯化钠的溶液,且二者均已达到饱和:

(1)A装置中所发生反应的离子方程式为                                   

C装置中稀硫酸的作用为                               

(2)下表中所列出的是相关物质在不同温度下的溶解度数据(g/100g水)

参照表中数据,请分析B装置中使用冰水是因为                               

(3)该校学生在检查完此套装置气密性后进行实验,结果没有得到碳酸氢钠晶体,指导教师指出应在          装置之间(填写字母)连接一个盛有                的洗气装置,其作用是                                      

(4)利用改进后的装置进行实验,在B中的试管内析出了晶体,经必要的操作后得到了一种纯净的晶体。现有下列试剂:盐酸、浓氨水、生石灰、蒸馏水,利用本题所提供的试剂(只限一种)及试管、酒精灯等主要仪器,通过简单实验判断该晶体是碳酸氢钠晶体,而不是碳酸氢铵或食盐晶体,简述操作方法、实验现象及结论:

                                                                              

                                                                             

(5)若该校学生进行实验时,所用饱和食盐水中含NaCl的质量为5.85g,实验后得到干燥的NaHCO3晶体的质量为5.04g,则NaHCO3的产率为                      

单项选择题