问题
填空题
设函数f(x)=
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答案
当x<2时,2x>1,可得 0<x<2,
当 x≥2时,
>1解得 x>3,2x x+3
分析可得,
f(x0)>1,则x0的取值范围是:(0,2)∪(3,+∞)
故答案为:(0,2)∪(3,+∞)
设函数f(x)=
|
当x<2时,2x>1,可得 0<x<2,
当 x≥2时,
>1解得 x>3,2x x+3
分析可得,
f(x0)>1,则x0的取值范围是:(0,2)∪(3,+∞)
故答案为:(0,2)∪(3,+∞)
完形填空。 | |||
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