问题 填空题
已知{
1
an
}是等差数列,且a2=
2
-1,a4=
2
+1,则a10=______.
答案

∵a2=

2
-1,a4=
2
+1,

1
a2
=
1
2
-1
=
2
+1
(
2
-1)(
2
+1)
=
2
+1

同理可得

1
a4
=
2
-1

由题意设数列{

1
an
}的公差为d,

1
a4
=
1
a2
+2d,解得d=-1,

所以

1
a10
=
1
a2
+8d
=
2
-7

故a10=

1
2
-7
=
2
+7
(
2
-7)(
2
-7)
=-
2
+7
47

故答案为:-

2
+7
47

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