问题
问答题
设函数f(x)，g(x)满足f’(x)=g(x)，g’(x)=2ex-f(x)，且f(0)=0，g(0)=2，求
．
答案
参考答案：由f’(x)=g(x)，g’(x)=2ex-f(x)，得f"(x)=2ex-f(x)
于是有
．解方程得f(x)=sinx-cosx+ex．
解析：[考点] 解函数方程
搜题请搜索小程序“爱下问搜题”
设函数f(x)，g(x)满足f’(x)=g(x)，g’(x)=2ex-f(x)，且f(0)=0，g(0)=2，求
．
参考答案：由f’(x)=g(x)，g’(x)=2ex-f(x)，得f"(x)=2ex-f(x)
于是有
．解方程得f(x)=sinx-cosx+ex．
解析：[考点] 解函数方程
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2. She is_________________.
4. She is________________ up leaves.
3. She is________________.
5. They are_______a________.