问题
解答题
在抛物线y=x2上求一点,使它到直线x-y-2=0的距离最短,并求此距离.
答案
最短距离为.
设(x0,x02)为抛物线上任一点,则
d=
=
≥.
当x0=时,即抛物线上点(
,
)到直线x-y-2=0的距离最短,最短距离为
.
在抛物线y=x2上求一点,使它到直线x-y-2=0的距离最短,并求此距离.
最短距离为.
设(x0,x02)为抛物线上任一点,则
d=
=
≥.
当x0=时,即抛物线上点(
,
)到直线x-y-2=0的距离最短,最短距离为
.
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