搜题请搜索小程序“爱下问搜题”
问题 单项选择题

下列关于软膏剂的概念正确叙述是( )

A．软膏剂系指药物与适宜基质混合制成的固体外用制剂
B．软膏剂系指药物与适宜基质混合制成的半固体外用制剂
C．软膏剂系指药物与适宜基质混合制成的半固体内服和外用制剂
D．软膏剂系指药物制成的半固体外用制剂
E．软膏剂系指药物与适宜基质混合制成的半固体内服制剂

答案

参考答案：B

完形填空
完形填空
       in the year 2020,New York will be a perfect place to live, Until then,many people will    1   to space
and live there.  2 _, New York is still the place to be. There will be   3   high buildings and homes. The
libraries will have computers, and you will be able to_4   books on them. All cinemas will have screens
(银幕) as   5   as the buildings on all of the walls. The restaurants will have robot waiters to   6   you food.
Schools will have teachers living in France to teach you   7   and teachers from ancient cities to teach you
history.  8    the help of televisions and computers,transportation will be quick and on time. If you want to
go to Africa,it will only  9    two hours by air. People will keep houses  10    by using the solar energy
(太阳能). In a word,the way people live will change a lot in the future.
( )1. A. walk    
( )2. A. And      
( )3. A. more    
( )4. A. watch    
( )5. A. big      
( )6. A. take    
( )7. A. English  
( )8. A. On      
( )9. A. pay      
( )10.A. warm     		B. move      
B. Because    
B. less      
B. see        
B. high      
B. bring      
B. Japanese  
B. With      
B. cost      
B. cool       		C. ride      
C. Though    
C. much      
C. read      
C. many      
C. make      
C. French    
C. In        
C. spend    
C. cold      		D. swim              
D. However          
D. fewer            
D. look at          
D. clean            
D. cook              
D. Chinese          
D. For              
D. take              
D. hot              
查看答案
单项选择题

设有以下定义和程序： #include＜iostream.h＞ class A1 { public: void show1() { cout＜＜"class A1"＜＜end1; } }; class A2:public A1 { public: void show2() { cout＜＜"class A2"＜＜end1; } }; class A3:protected A2 { public: void show3() {cout＜＜"class A1"＜＜end1; } }; void main() { A1 obj1; A2 obj2; A3 obj3; } 则以下不合语法的调用语句是( )。

A．obj1.show1();

B．obj2.show1();

C．obj3.show1();

D．obj2.show2();
查看答案