问题
选择题
已知等差数列{an}的前n项和为Sn,a3+a8=13,且S7=35.则a7=( )
A.11
B.10
C.9
D.8
答案
由等差数列的性质可得:
S7=
=7(a1+a7) 2
=35,解得a4=5,7×2a4 2
又a3+a8=a4+a7=13,故a7=8,
故选D
已知等差数列{an}的前n项和为Sn,a3+a8=13,且S7=35.则a7=( )
A.11
B.10
C.9
D.8
由等差数列的性质可得:
S7=
=7(a1+a7) 2
=35,解得a4=5,7×2a4 2
又a3+a8=a4+a7=13,故a7=8,
故选D