问题
选择题
椭圆C 1:
|
答案
设PK垂直于准线 l,K为垂足,由题意和椭圆的定义可得
-|F1F2| |PF1|
=|PF1| |PF2|
-2c 2a - |PF2| |PF1| |PK|
=
-e=2c 2a - |PF2|
=2c-
(2a-|PF2|)c a 2a - |PF2|
=
|PF2|c a 2a - |PF2|
=
|PK |c a 2a - |PK |
•c a PK |PF1|
=
•c a
=1,a c
故选 B.