问题
填空题
已知{an}是等差数列,且公差d≠0,又a1,a2,a4依次成等比数列,则
|
答案
由{an}是等差数列,所以,a2=a1+d,a4=a1+3d,
又a1,a2,a4依次成等比数列,所以,a22=a1a4,
即(a1+d)2=a1(a1+3d),所以,a1d=d2,因为d≠0,所以,a1=d.
则
=a1+a4+a10 a2+a1+a4
=3a1+12d 3a1+4d
=15d 7d
.15 7
故答案为
.15 7