已知Sn是等差数列{an}的前n项和,若a3-a8+a11+a15=4,则S15-S5的值是( )
A.5
B.8
C.16
D.20
设等差数列{an}的公差为d,则a3-a8+a11+a15
=(a1+2d)-(a1+7d)+(a1+10d)+(a1+14d)
=2a1+19d=4,
而S15-S5=15a1+
d-(5a1+15×14 2
d)5×4 2
=10a1+95d=5(2a1+19d)=5×4=20
故选D
已知Sn是等差数列{an}的前n项和,若a3-a8+a11+a15=4,则S15-S5的值是( )
A.5
B.8
C.16
D.20
设等差数列{an}的公差为d,则a3-a8+a11+a15
=(a1+2d)-(a1+7d)+(a1+10d)+(a1+14d)
=2a1+19d=4,
而S15-S5=15a1+
d-(5a1+15×14 2
d)5×4 2
=10a1+95d=5(2a1+19d)=5×4=20
故选D