问题 填空题
已知等差数列an满足:a3=7,a5+a7=26,令bn=
1
a2n
-1
(n∈N*)
,则数列bn的前n项和Tn=______.
答案

∵等差数列an满足:a3=7,a5+a7=26,

∴a3+a5+a7=33,

∴a5=11

∴d=

11-7
2
=2

∴an=2n+1,

bn=

1
an2
-1
=
1
4n(n+1)

∴4Tn=

1
1×2
+
1
2×3
+…+
1
n(n+1)

=1-

1
2
+
1
2
-
1
3
+…+
1
n
-
1
n+1
=
n
n+1

Tn =

n
4(n+1)

故答案为:

n
4(n+1)

解答题
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