问题
填空题
已知等差数列an满足:a3=7,a5+a7=26,令bn=
|
答案
∵等差数列an满足:a3=7,a5+a7=26,
∴a3+a5+a7=33,
∴a5=11
∴d=
=211-7 2
∴an=2n+1,
∴bn=
=1
-1a n2 1 4n(n+1)
∴4Tn=
+1 1×2
+…+1 2×3 1 n(n+1)
=1-
+1 2
-1 2
+…+1 3
-1 n
=1 n+1 n n+1
∴Tn =n 4(n+1)
故答案为:n 4(n+1)