问题
填空题
一次函数y=-
|
答案
由题意,令x=0,y=
,1 k+1
∴Bk(0,
),1 k+1
令y=0,x=
,1 k
∴Ak(
,0),1 k
∴Sk=
•1 2
•1 k
=1 k+1
=1 2k(k+1)
(1 2
-1 k
)1 k+1
∴S1+S2+…+S2006=
(1 2
+1 1×2
+…+1 1×3
)1 2011×2012
=
(1-1 2
+1 2
-1 2
+1 3
-1 3
+…+1 4
-1 2011
)1 2012
=
(1-1 2
)1 2012
=
.2011 4024
故答案为:
.2011 4024