问题
填空题
等差数列{an}和{bn}的前n项和分别为Sn和Tn,且
|
答案
由
=Sn Tn
=2n 3n+1
=n(a1+an) 2 n(b1+bn) 2
,a1+an b1+bn
而
=a5 b5
=
(a1+a9) 9 2
(b1+b9) 9 2 a1+a9 b1+b9
即当n=9时,
=a5 b5
=Sn Tn
=2n 3n+1
=18 28 9 14
故答案为9 14