问题
选择题
等差数列{an}和{bn}中,a1+b100=100,b1+a100=100,则数列{an+bn}的前100项之和为( )
A.0
B.100
C.1000
D.10000
答案
∵{an}、{bn}都是等差数列,
∴{an+bn}是等差数列,
∵a1+b100=100,b1+a100=100,
∴a1+b1+a100+b100=200,
∴S100=
=100(a1+b1+a100+b100) 2
=10000,100×200 2
故选D.