问题
选择题
设Sn是等差数列{an}的前n项和,已知S6=36,Sn=324,Sn-6=144,则n=( )
A.15
B.16
C.17
D.18
答案
∵Sn=324,Sn-6=144,
∴Sn-Sn-6=an-5+an-4+…+an=180
又∵S6=a1+a2+…+a6=36,a1+an=a2+an-1=a6+an-5,
∴6(a1+an)=36+180=216
∴a1+an=36,由Sn=
=18n=324,(a1+an)n 2
∴n=18
故选D