问题 选择题

设Sn是等差数列{an}的前n项和,已知S6=36,Sn=324,Sn-6=144,则n=(  )

A.15

B.16

C.17

D.18

答案

∵Sn=324,Sn-6=144,

∴Sn-Sn-6=an-5+an-4+…+an=180

又∵S6=a1+a2+…+a6=36,a1+an=a2+an-1=a6+an-5

∴6(a1+an)=36+180=216

∴a1+an=36,由Sn=

(a1+an)n
2
=18n=324,

∴n=18

故选D

选择题
解答题