问题 填空题 若x,y为实数,满足x-1+(3x+y-1)2=0,则±5x+y2=______. 答案 ∵x-1+(3x+y-1)2=0∴x-1=03x+y-1=0,解得x=1y=-2则±5x+y2=±5×1+(-2)2 =±3.