已知等比数列{an}中,各项都是正数,且2a2,
|
设等比数列的公比为q,则
∴2a2,
a1,3a3成等差数列,1 2
∴a1=2a2+3a3
∴a1=2a1q+3a1q2
∴1=2q+3q2
∴q=-1或q=1 3
∵等比数列{an}中,各项都是正数,
∴q=1 3
∴
=a6+a7 a8a10
=a6+a7 a9
=361+q q3
故选C.
已知等比数列{an}中,各项都是正数,且2a2,
|
设等比数列的公比为q,则
∴2a2,
a1,3a3成等差数列,1 2
∴a1=2a2+3a3
∴a1=2a1q+3a1q2
∴1=2q+3q2
∴q=-1或q=1 3
∵等比数列{an}中,各项都是正数,
∴q=1 3
∴
=a6+a7 a8a10
=a6+a7 a9
=361+q q3
故选C.