问题 单项选择题

流行病学研究发现某种暴露与两种不同的疾病X和Y有联系。对疾病X的相对危险度为6.0,特异危险度为 5%;对疾病Y的相对危险度为3.0,特异危险度为20%。据此,可以得出如下结论

A.暴露与疾病X的联系强度是与疾病 Y的联系强度的4倍
B.在未暴露者中,发生疾病Y的人数将是发生疾病X的人数的4倍
C.消除暴露后,减少的疾病Y的发病人数和减少的疾病X的发病人数将不同
D.在暴露者中,发生疾病X的人数将是发生疾病Y的人数的2倍
E.在暴露者中,疾病X的发病率比疾病Y高15%

答案

参考答案:C

阅读理解

阅读理解

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