问题
选择题
不论x取何值,x-x2-1的值都( )
|
答案
x-x2-1=-(x2-x)-1=-(x2-x+
-1 4
)-1=-[(x-1 4
)2-1 2
]-1=-(x-1 4
)2+1 2
-1=-(x-1 4
)2-1 2 3 4
∵(x-
)2≥01 2
∴-(x-
)2≤01 2
∴-(x-
)2-1 2
≤-3 4 3 4
故选B.
不论x取何值,x-x2-1的值都( )
|
x-x2-1=-(x2-x)-1=-(x2-x+
-1 4
)-1=-[(x-1 4
)2-1 2
]-1=-(x-1 4
)2+1 2
-1=-(x-1 4
)2-1 2 3 4
∵(x-
)2≥01 2
∴-(x-
)2≤01 2
∴-(x-
)2-1 2
≤-3 4 3 4
故选B.