以下程序的输出结果是【 】。 #include＜iostream．h＞ unsignedfun(unsignednum) { unsignedk=1； do { k * =num%10；num/=10；}while(num)； returnk； } voidmain( ) { unsignedn=26； cout＜＜fun(n)＜＜endl； ＝
参考答案：L
解析：函数有一个形参num，循环前变量k置1，循环中，表达式num%10是取num 的个位，将num的个位值累乘于k中，然后num除以10。循环直至num为。结束，这是 逐一求出num十进制表示的各位数字，并累乘于变量k的循环。函数最后返回k。函数 fun的功能是求整数的各位十进数字积。
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