有以下程序：#includestruct STU{charname[10];intnum;};void f(char*name,intnum){ struct STUs[2]={{"SunDan",20044},{"Penghua",20045}};num=s[0].num;strcpy(name,s[0].name);}main(){ struct STUs[2]={{"YangSan",20041},{"LiSiGao",20042}},*p;p=&s[1];f(p->name,p->num);printf("%s%d\n",p->name,p->num);}程序运行后的输出结果是______。

A．SunDan 20042

B．SunDan 20044

C．LiSiGuo 20042

D．YangSan 20041

宁夏内陆开放型试验区的开放优势有哪些？