问题
选择题
若向量
|
答案
•an
+2n=(cos2nθ,sinnθ)(1,2sinnθ)+2nbn
=cos2nθ+2sinnθsinnθ+2n
=1-2sin2nθ+2sin2nθ+2n
=2n+1
满足等差数列的通项公式
∴数列{
•an
+2n}是等差数列bn
故选A.
若向量
|
•an
+2n=(cos2nθ,sinnθ)(1,2sinnθ)+2nbn
=cos2nθ+2sinnθsinnθ+2n
=1-2sin2nθ+2sin2nθ+2n
=2n+1
满足等差数列的通项公式
∴数列{
•an
+2n}是等差数列bn
故选A.