欲配制500mL的0.1mol/LHCl溶液，应量取c（HCl）=11.8mol/L

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问题问答题简答题

欲配制500mL的0.1mol/LHCl溶液，应量取c（HCl）=11.8mol/L的浓HCl多少mL？

答案

参考答案：

设应取xmL，则500mLх0.1mol/L=11.8mol/LхxmL

解方程，得x=4.24mL

4.24mL

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