问题
填空题
等差数列{an}中,S20=30,则a3+a18=______.
答案
∵S20=30,∴
=30,解得a1+a20=3,20(a1+a20) 2
∴a3+a18=a1+a20=3,
故答案为:3.
等差数列{an}中,S20=30,则a3+a18=______.
∵S20=30,∴
=30,解得a1+a20=3,20(a1+a20) 2
∴a3+a18=a1+a20=3,
故答案为:3.