问题
填空题
设实数x、y满足x2+4y2+2x-4y+2=0,则x2y+2x
|
答案
由题意知,x2+4y2+2x-4y+2=0变形得,(x+1)2+(2y-1)2=0
∴(x+1)2=0,x=-1
(2y-1)2=0,y=1 2
把x、y代入x2y+2x
得:原式=(-1)2×y
+2×(-1)×1 2
=-1-1 2
.2
设实数x、y满足x2+4y2+2x-4y+2=0,则x2y+2x
|
由题意知,x2+4y2+2x-4y+2=0变形得,(x+1)2+(2y-1)2=0
∴(x+1)2=0,x=-1
(2y-1)2=0,y=1 2
把x、y代入x2y+2x
得:原式=(-1)2×y
+2×(-1)×1 2
=-1-1 2
.2