问题 选择题

下列离子方程式中正确的是(  )

A.Al(OH)3滴加稀盐酸:OH-+H+=H2O

B.Fe片浸泡在FeCl3溶液中:Fe3++Fe=2Fe2+

C.NaHSO4溶液中加BaCl2溶液:SO42-+Ba2+=BaSO4

D.AlCl3溶液中滴加氨水:Al3++3OH-=Al(OH)3

答案

A.Al(OH)3滴加稀盐酸的离子反应为Al(OH)3+3H+=3H2O+Al3+,故A错误;

B.Fe片浸泡在FeCl3溶液中的离子反应为2Fe3++Fe=3Fe2+,故B错误;

C.NaHSO4溶液中加BaCl2溶液的离子反应为SO42-+Ba2+=BaSO4↓,故C正确;

D.AlCl3溶液中滴加氨水的离子反应为Al3++3NH3.H2O=Al(OH)3↓+3NH4+,故D错误;

故选C.

完形填空
完形填空。
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单项选择题 A1型题