情景对话。

     根据对话情景和内容，从对话后所给的选项中选出能填入每一空白处的最佳选项。

— What's the matter with you, Tom?

— Oh,   1   Maybe I've got a cold. 

—   2   Why don't you take some cold stop?

—  3 

—  That's what I took the last time I had a cold.    4   Maybe that'll help.

— Thanks.

(Two days later )

— How are you feeling now?

— Getting better.

—   5   

A. Does it work well?

B. Good idea.

C. Glad to hear it.

D. I feel a little bad under the weather now.

E. It worked pretty well.

F. It's very kind of you.

G. That's too bad.

论述题3： 已知C源程序如下： /*longIntAdd*/ #include＜stdio.h＞ #include＜string.h＞ #define LENGTH 81 void addLInt(char s1[],char s2[]); void reverse(char s[]); int main() { char intstr1[LENGTH],intstr2[LENGTH]; printf("请输入超长整数的被加数和加数:\n"); scanf("%s%s",intstr1,intstr2); addLInt(intstr1,intstr2); printf("超长整数和为:%s",intstr1); return 0; } void addLInt(char s1[],char s2[]) { int i=0,tmp,c=0; char s[LENGTH]; if(strlen(s1)＜strlen(s2)){ strcpy(s,s1); strcpy(s1,s2); strcpy(s2,s); } reverse(s1);reverse(s2); while(s2[i]!=;\0’){ tmp=s1[i]-’0’+s2[i]-’0’+c; 81[i]=tmp%10+’0’; c=tmp/10; i++; } while(si[1]!=’\0’&&c){ tmp=s1[i]-’0’+c; s1[i]=tmp%10+’0’; c=tmp/10; i++; } If(c){ s1[i++]=c+’0’; s1[i]=’\0’; } reverse(s1); } void reverse(char s[]) { int i,j,c; for(i=0,j=strlen(s)-1;i＜j;i++,j--){ c=s[i]; s[i]=s[j]; s[j]=c; } }

画出程序中函数addLInt的控制流程图；