问题
选择题
等差数列{an}中,a4+a10+a16=30,则a18-2a14的值为( )
A.-20
B.-10
C.10
D.20
答案
∵a4+a10+a16=30,
∴3a10=30,
∴a10=10,
又∵a18-2a14=4d-a14=-a10=-10
故选B
等差数列{an}中,a4+a10+a16=30,则a18-2a14的值为( )
A.-20
B.-10
C.10
D.20
∵a4+a10+a16=30,
∴3a10=30,
∴a10=10,
又∵a18-2a14=4d-a14=-a10=-10
故选B