问题
填空题
计算:
(1)a2•a3=______.
(2)(a3)2=______.
(3)(x2)3•x7=______.
(4)(-a3)4+(-a4)3=______.
答案
(1)原式=a5,
故答案为:a5.
(2)原式=a6,
故答案为:a6.
(3)原式=x5•x7
=x12,
故答案为:x12.
(4)原式=a12-a12
=0,
故答案为:0.
计算:
(1)a2•a3=______.
(2)(a3)2=______.
(3)(x2)3•x7=______.
(4)(-a3)4+(-a4)3=______.
(1)原式=a5,
故答案为:a5.
(2)原式=a6,
故答案为:a6.
(3)原式=x5•x7
=x12,
故答案为:x12.
(4)原式=a12-a12
=0,
故答案为:0.