问题
填空题
已知:实数x,y满足4x2+2xy+y2-y+4=4
|
答案
(3x2-y)-4
+4+x2+2xy+y2=0,3x2-y
(
-2)2+(x+y)2=0,3x2-y
∴
-2=0,x+y=0,解得3x2-y
或x=- 4 3 y= 4 3
,x=1 y=-1
∴以x,y为根的一元二次方程为t2-
=0,或t2-1.16 9
故答案为:t2-
=0,或t2-1=0.16 9
已知:实数x,y满足4x2+2xy+y2-y+4=4
|
(3x2-y)-4
+4+x2+2xy+y2=0,3x2-y
(
-2)2+(x+y)2=0,3x2-y
∴
-2=0,x+y=0,解得3x2-y
或x=- 4 3 y= 4 3
,x=1 y=-1
∴以x,y为根的一元二次方程为t2-
=0,或t2-1.16 9
故答案为:t2-
=0,或t2-1=0.16 9