问题
填空题
计算:-3x•(2x2-x+4)=______;(-2x2y3)2=______.
答案
-3x•(2x2-x+4)=-6x3+3x2-12x;
(-2x2y3)2=4x4y6.
故答案为:-6x3+3x2-12x,4x4y6.
计算:-3x•(2x2-x+4)=______;(-2x2y3)2=______.
-3x•(2x2-x+4)=-6x3+3x2-12x;
(-2x2y3)2=4x4y6.
故答案为:-6x3+3x2-12x,4x4y6.