问题 选择题
设(an+12=
1
10
(an2,n∈N*,an>0,令bn=lgan则数列{bn}为(  )
A.公差为正数的等差数列B.公差为负数的等差数列
C.公比为正数的等比数列D.公比为负数的等比数列
答案

∵(an+12=

1
10
(an2,an>0,

an+1
an
=
1
410

lg

an+1
an
=-
1
4

∴lgan+1-lgan=-

1
4

∵bn=lgan

∴bn+1-bn=-

1
4

∴数列{bn}为公差为负数的等差数列,

故选B.

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