问题
填空题
计算: (1)(2×103)2=______. (2)-(3x2y)2=______. (3)(-
|
答案
(1)原式=22×(103)2
=4×106;
(2)原式=-9x2×2y2
=-9x4y2;
(3)原式=(-
)2a2×2b1×23 4
=
a4b2.9 16
故答案为:4×106.-9x4y2.
a4b2.9 16
计算: (1)(2×103)2=______. (2)-(3x2y)2=______. (3)(-
|
(1)原式=22×(103)2
=4×106;
(2)原式=-9x2×2y2
=-9x4y2;
(3)原式=(-
)2a2×2b1×23 4
=
a4b2.9 16
故答案为:4×106.-9x4y2.
a4b2.9 16