问题
填空题
设Sn是等差数列{an}的前n项和,若
|
答案
由等差数列的性质可得S3,S6-S3,S9-S6,S12-S9成等差数列,
由
=S3 S6
可得S6=3S3,故S6-S3=2S3,1 3
故S9-S6=3S3,S12-S9=4S3,
解之可得S9=6S3,S12=10S3,
故
=S6 S12
=3S3 10S3 3 10
故答案为:3 10
设Sn是等差数列{an}的前n项和,若
|
由等差数列的性质可得S3,S6-S3,S9-S6,S12-S9成等差数列,
由
=S3 S6
可得S6=3S3,故S6-S3=2S3,1 3
故S9-S6=3S3,S12-S9=4S3,
解之可得S9=6S3,S12=10S3,
故
=S6 S12
=3S3 10S3 3 10
故答案为:3 10