问题
解答题
已知|ab-2|+(b-1)2=0,试求
|
答案
根据题意得:
,ab-2=0 b-1=0
解得:
,a=2 b=1
则原式=
+1 3×2
+1 4×3
=1 5×4
-1 2
+1 3
-1 3
+1 4
-1 4
=1 5
-1 2
=1 5
.3 10
已知|ab-2|+(b-1)2=0,试求
|
根据题意得:
,ab-2=0 b-1=0
解得:
,a=2 b=1
则原式=
+1 3×2
+1 4×3
=1 5×4
-1 2
+1 3
-1 3
+1 4
-1 4
=1 5
-1 2
=1 5
.3 10