问题
解答题
化简或求值 (1)4(m2+n)+2(n-2m2) (2)5ab2-[a2b+2(a2b-3ab2)] (3)已知(x+1)2+|y-2|=0.求
(4)如果代数式(2x2+ax-y+1)-(2bx2-3x+5y-4)的值与字母x所取的值无关,试求代数式
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答案
(1)原式=4m2+4n+2n-4m2
=6n;
(2)原式=5ab2-a2b-2a2b+6ab2
=-3a2b+11ab2;
(3)∵(x+1)2+|y-2|=0,
∴x+1=0或y-2=0,
解得:x=-1,y=2,
原式=
x-2x+1 2
y-2 3
x+3 2
y1 3
=y-3x
=2+3
=5;
(4)(2x2+ax-y+1)-(2bx2-3x+5y-4)
=2x2+ax-y+1-2bx2+3x-5y+4
=(2-2b)x2+(a+3)x-6y+5,
∵此多项式与x的取值无关,
∴2-2b=0,且a+3=0,
解得:a=-3,b=1,
则原式=
a3-2b2-1 3
a3+3b21 4
=
a3+b21 12
=
×(-27)+31 12
=-
.5 4