问题
解答题
计算: (1)-32-(-2)2; (2)-14-
(3)(-10)2+[(-4)2-(3+32)×2]; (4)(-1)4-(1-0.5)×
(5)-0.52+
(7)(-2)2003+(-2)2002; (8)(-0.25)2009×42008. |
答案
(1)-32-(-2)2-9-4
=-13;
(2)-14-
×[2-(-3)2]1 6
=-1-
×(-7)1 6
=-1+7 6
=
;1 6
(3)(-10)2+[(-4)2-(3+32)×2]
=100+(16-24)
=92;
(4)(-1)4-(1-0.5)×
×[2-(-2)2]1 3
=1-
×(-2)1 6
=1
;1 3
(5)-0.52+
-|-22-4|-(-11 4
)3×1 2 4 9
=-0.25+
-8+1 4
×27 8 4 9
=-6.5;
(6)(-2)3-3×[(-4)2+2]-(-3)2÷(-2)
=(-8)-3×18+9 2
=(-8)-54+9 2
=-62+9 2
=-
;115 2
(7)(-2)2003+(-2)2002
=-22003+22002
=-22002×2+22002
=22002×(-2+1)
=-22002;
(8)(-0.25)2009×42008
=-(
)2009×420081 4
=-
×(1 4
×4)20081 4
=-
.1 4