问题 解答题
(1)计算:3
7
-
1
2
7
+2
7
-
3
2
7

(2)计算:(2
2
-
7
8
)2-(2
2
+
7
8
)2

(3)
-(
1
27
)
-
1
3
+(
19
)
2

(4)(
1
5
)
1
2
×(
3
5
)-
1
2
×(
3
25
)
1
2

(5)
642
×
8
÷
62

(6)(
6
-2
15
3
-6
1
2

(7)
2
×
3
÷
1
2
+
(-3)2+(
7
)
2
;  
(8)5-
1
2
×5
1
2
+(2
1
2
÷3
1
2
)-3
(结果用幂的形式表示)
答案

(1)原式=3

7

(2)原式=(2

2
-
7
8
+2
2
+
7
8
)(2
2
-
7
8
-2
2
-
7
8
)=4
2
×(-
7
4
)=-7
2

(3)原式=-

-3+19
=
16
=4;

(4)原式=

1
5
×
5
3
×
3
25
=
1
5
×
5
3
×
3
25
=
1
5

(5)原式=4

2
6
×2×2
1
2
÷2
1
6
=2
2
3
×2×2
1
2
÷2
1
6
=2
2
3
+1+
1
2
-
1
6
=22=4;

(6)原式=

6×3
-2
15×3
-3
2
=3
2
-6
5
-3
2
=-6
5

(7)原式=

2
×
3
×
2
+
9+7
=2
3
+4;

(8)原式=5-

1
2
+
1
2
+(
3
2
 
3
2
=50+
3
3
2
2
3
2
=1+
3
3
2
2
3
2

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