已知(2a-1)2+|3b-1|=0,求5(3a2b-ab2)-(ab2+3a2b)的值.
∵(2a-1)2+|3b-1|=0,
∴2a-1=0,3b-1=0,即a=
,b=1 2
,1 3
则5(3a2b-ab2)-(ab2+3a2b)
=15a2b-5ab2-ab2-3a2b
=12a2b-6ab2
=1-1 3
=
.2 3
已知(2a-1)2+|3b-1|=0,求5(3a2b-ab2)-(ab2+3a2b)的值.
∵(2a-1)2+|3b-1|=0,
∴2a-1=0,3b-1=0,即a=
,b=1 2
,1 3
则5(3a2b-ab2)-(ab2+3a2b)
=15a2b-5ab2-ab2-3a2b
=12a2b-6ab2
=1-1 3
=
.2 3